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-   -   HobbyWing EZRun 80A Review (https://www.rc-monster.com/forum/showthread.php?t=18727)

mjderstine 03.23.2009 02:29 PM

awesome, now i can get the card, and the esc at one awesome store. good stuff.

Joey 04.13.2009 03:26 PM

Any news on if it handles 5s????????????

BrianG 04.13.2009 03:30 PM

I did run it a little bit on 5s. It arms and runs. Just don't know for how long. I didn't want to run it for too long as it was on a 1512/2d and the current would be rather high.

lincpimp 04.13.2009 05:18 PM

Has anyone tried this with a sensored motor yet?

BrianG 04.13.2009 05:22 PM

Sensored? What's that? :wink:

Joey 04.14.2009 12:19 AM

Quote:

Originally Posted by BrianG (Post 278994)
I did run it a little bit on 5s. It arms and runs. Just don't know for how long. I didn't want to run it for too long as it was on a 1512/2d and the current would be rather high.

Wouldnt the current be lower on 5S than 4S?

BrianG 04.14.2009 12:24 AM

Not if the gearing and the motor is the same. A=V/R. If voltage goes up, and resistance stays the same, current will go up. I'd have to drop gearing and/or use a lower kv motor (increasing R) to reduce current.

himalaya 04.14.2009 01:47 AM

Quote:

Originally Posted by BrianG (Post 279134)
Not if the gearing and the motor is the same. A=V/R. If voltage goes up, and resistance stays the same, current will go up. I'd have to drop gearing and/or use a lower kv motor (reducing R) to reduce current.

Guess you were trying to say (increasing R & inductance) to reduce current. :yes:

BrianG 04.14.2009 09:46 AM

lol, yeah, I meant increasing R...original post edited. :oops:

I have an excuse: it was late and I was tired. :tongue:

Joey 04.14.2009 06:59 PM

Quote:

Originally Posted by BrianG (Post 279134)
Not if the gearing and the motor is the same. A=V/R. If voltage goes up, and resistance stays the same, current will go up. I'd have to drop gearing and/or use a lower kv motor (increasing R) to reduce current.

But Power = current X voltage ---- P=IV

So to produce the same power with higher voltage, current drops. In effect this equation is more direct to the VI relationship than I = V/R isnt it?

littlegiant 04.14.2009 07:55 PM

Quote:

Originally Posted by Joey (Post 279272)
But Power = current X voltage ---- P=IV

So to produce the same power with higher voltage, current drops. In effect this equation is more direct to the VI relationship than I = V/R isnt it?

If u are running on 5S without changing your gearing, your truck will be running faster. Which means that the power is higher. P=IV and so your current will definitely be higher.

In order for your 5S to have a lower current than a 4S, it should be geared to your current 4S speeds. If your 5S is running at a higher speed, you are just running your motor at a higher wattage.

Cain 05.08.2009 09:40 PM

Has anyone taken a look at the speedpassion ESC internals and compared it to this one? Have heard that they are basically the same.

lutach 05.09.2009 07:59 AM

Quote:

Originally Posted by Cain (Post 285648)
Has anyone taken a look at the speedpassion ESC internals and compared it to this one? Have heard that they are basically the same.

They are the same.

Cain 05.09.2009 09:46 AM

got a link to this discussion?

lutach 05.09.2009 10:16 AM

Quote:

Originally Posted by Cain (Post 285742)
got a link to this discussion?

There's no link, it's just the facts. You can also ask Hobbywing who's a member of RCM.


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