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Pdelcast 01.14.2011 10:09 AM

Quote:

Originally Posted by nuz69 (Post 393937)
Patrick, this isn't exactly right, there is a small amount of power which is lost in the bearings and in the air friction no ? :lol:
The motor is not really at "no load" but "air loaded".
Maybe it's only 0,5 or 1% of the no load power... What's your opinion about aerodynamics and bearings losses ?
(I doubt that a lot power is lost in the bearings anyway, other than that they would be quickly ripped apart...)

Yes, that's true -- bearing losses and "windage" (air drag) figure into the no-load losses. I just simplified it a bit because the majority of the losses are magnetic.

To determine what the bearing and windage losses are, you can measure no load current at, say, 6V and at 10V. The difference (usually very small) will be the contribution of bearing and windage losses.

Pdelcast 01.14.2011 10:17 AM

Quote:

Originally Posted by sikeston34m (Post 393845)
Thank you Patrick. I've pondered some of these variables, back when I was experimenting with rewinding outrunner motors. John Rob and I were playing around with some ideas at the time.

I wonder why the thinner laminations work so much better at conducting magnetism? I'm sure it has alot to do with, the core of the lamination isn't what does the work since the magnetism follows surface area. The greater number of laminations in the same amount of space equals more surface area, thus conducting more magnetism overall.

I was glad to see that you chose a comparable kv rating for no load current. Kv does directly affect no load current, correct?

Resistive losses change from one motor wind to the next. I'm sure this is why a 1 or 2 turn motor has less overall resistence.

I know this isn't practical, but for the sake of efficiency, wouldn't a motor wound with silver wire work better than copper?

Overall resistence is also based on how good of a conductor, the wind wire is.

Guys, I have a feeling what Patrick posted here is "in a nutshell". I'm sure there's ALOT more to "the big picture".

As Brian said earlier, the thinner laminations allow fewer eddy currents to form that are perpendicular to the magnetic field, and resist the field.
This is the same reason why high electrical resistance is a good thing -- the eddy currents that do form will be lower in power if the resistance of the steel is high.

Silver is a better conductor than copper, but costs so much that it's not practical. And it's only a little bit (I think about 20% or so) better than copper.

And it's not just the cost of the metal -- it's the processing too. There are very few manufacturers that are setup to process silver into electrical wire, and there are a few applications which demand it (some space applications.) So they command a HUGE premium. After processing, silver wire is around $2500 a pound. That would make a 1515 cost somewhere in the $600.00-$800.00 (just an estimate!!!) range. :lol:

brushlessboy16 01.14.2011 12:26 PM

Quote:

Originally Posted by Pdelcast (Post 393950)
As Brian said earlier, the thinner laminations allow fewer eddy currents to form that are perpendicular to the magnetic field, and resist the field.
This is the same reason why high electrical resistance is a good thing -- the eddy currents that do form will be lower in power if the resistance of the steel is high.

Silver is a better conductor than copper, but costs so much that it's not practical. And it's only a little bit (I think about 20% or so) better than copper.

And it's not just the cost of the metal -- it's the processing too. There are very few manufacturers that are setup to process silver into electrical wire, and there are a few applications which demand it (some space applications.) So they command a HUGE premium. After processing, silver wire is around $2500 a pound. That would make a 1515 cost somewhere in the $600.00-$800.00 (just an estimate!!!) range. :lol:


Have you ever thought of making a limited run of like "ultimate motors"

Like a batch of 150 1515's with silver angel hair wire, 1mm air gap, monster magnets and low drag bearings..


expensive yest. but with your PR you could market it and it would probably sell out..


...not to mention that the motors would be absolutely INSANE!

lincpimp 01.14.2011 01:34 PM

Since we are discussing motor designs I have a few questions...

I had 2 of the old feigao xl can motors. 2 pole and cheap!!! I had a 14xl that I ran on 8s, and a 7xl that I ran on 4s. In the same weight vehicle with the same gearing (thus load) the 14xl ran cooler.

I am guessing the motors use the same materials and construction techniques. Are lower kv motors more effecient just due to design? Higher turn motors use thinner wire and more of it, is that inherently more effecient?

Just wondering. The 7xl was very gearing sensitive to keep temps down to "reasonable" levels. while the 14xl did not seem to mind. Amp draw must have some bearing, as less amps means less heat.

sikeston34m 01.14.2011 02:34 PM

Quote:

Originally Posted by lincpimp (Post 393978)
Since we are discussing motor designs I have a few questions...

I had 2 of the old feigao xl can motors. 2 pole and cheap!!! I had a 14xl that I ran on 8s, and a 7xl that I ran on 4s. In the same weight vehicle with the same gearing (thus load) the 14xl ran cooler.

I am guessing the motors use the same materials and construction techniques. Are lower kv motors more effecient just due to design? Higher turn motors use thinner wire and more of it, is that inherently more effecient?

Just wondering. The 7xl was very gearing sensitive to keep temps down to "reasonable" levels. while the 14xl did not seem to mind. Amp draw must have some bearing, as less amps means less heat.

The 14xl had two things going for it that the 7xl did not have.

#1. Lower kv - more torque to overcome the the mechanical resistence.

#2. Higher Voltage - This goes back to the Watts = Amps X Voltage law.

Think of it this way. It takes X number of Watts to accelerate the test vehicle. Less Amp Draw equals less heat.

The 14xl was taking advantage of the higher voltage, thus the amp draw was substantially less. Probably 50% of what the 7xl was drawing to do the same amount of work.

nuz69 01.14.2011 03:15 PM

Theoretically no. The 14XL has necessarily THINNER windings, therefore the windings heats more than the 7XL for the same amp. The thickness is lower as the turns is bigger, or the Kv lower (same space, longer windings ==> thinner windings). So theoretically a 8S 14XL setup will produce same heat than a 4S 7XL setup.
For example, a 1515/1Y and a 1515/2Y, both 4S. The 1515/2Y will run a lot hoter in current buggy or truggy setup. The 2Y needs higher voltage (8S) to run efficiently. But therefore, the resistive losses are smaller in the ESC, but you need a 8S ESC...
Higher Kv means less torque per amp (torque said alone means nothing).
Maybe, when the windings are thinner (14XL) they better fulfill the motor ? Just weight your two motor and see wich one is heavier ?

BrianG 01.14.2011 03:21 PM

You have to remember the resistive losses come from I^2*R. True, resistance is higher in a higher turn motor because of the added turns and thinner wire, but less current makes a bigger difference because that is the squared part of the equation. So, as long as the top speed is the same (load), a higher voltage on a lower kv will result in the same amount of work and same overall power as a lower kv/voltage setup.

nuz69 01.14.2011 03:24 PM

Briang, you forgot that the resistance depends of the length AND the surface of the wire ;) For the same volume of matter (or same weight for both motor), a wire twice more more long have a resistance four times higher.
R = R0 * length/surface and you have to keep length*surface equal for both motor (volume or weight).
So the multiplication R*IČ would be exactly the same.
For example, I am sure that the 1515/2Y motor resistance is average 4 time higher than the 1515/1Y one.

lincpimp 01.14.2011 03:43 PM

Geared for the same speed the 2 motors should "see" the same load. I just wondered why the 14xl ran cooler. I just figured the amp draw thru the motor (if there is such a thing) was around half as much with the 14xl than the 7xl, and that accounted for the addl heat created. Higher amp draw seems to produce more heat as the wires and such have to transmit it.

I may be completely wrong on this, so that is why I asked!

Thanks for the replys.

reno911 01.14.2011 04:02 PM

Cool thread lots of info here. Thanks a bunch.

Also, I am surprised to see so many copies, I was only aware of Leopard. Now there seem to be tons of them.

phatmonk 01.28.2011 10:48 AM

Does the no load current increase as the volts increase?Also does the kv effect the no load current.

Pdelcast 01.28.2011 10:55 AM

Quote:

Originally Posted by phatmonk (Post 395604)
Does the no load current increase as the volts increase?Also does the kv effect the no load current.

It does, slightly. The no-load current goes up because of windage (air resistance) and bearing drag. But it's not linear with voltage ... not even close. A motor that is 4.0A at 7 volts might be around 5.0A at 20 volts.

A RC Dude 06.18.2013 07:10 PM

Quote:

Originally Posted by lincpimp (Post 393994)
Geared for the same speed the 2 motors should "see" the same load. I just wondered why the 14xl ran cooler. I just figured the amp draw thru the motor (if there is such a thing) was around half as much with the 14xl than the 7xl, and that accounted for the addl heat created. Higher amp draw seems to produce more heat as the wires and such have to transmit it.

I may be completely wrong on this, so that is why I asked!

Thanks for the replys.

If you took the time to write out all the many many equations to get to the bottom of the question, i bet you'll find that the the efficiency is not dependent on the size or turn count. I bet the difference in heat comes from nothing more then the size of the motor.

The 14xl has two things keeping it cooler:
1. The more surface area allows it to cool off better, especially over time.
This is why larger, more powerful ESC's require heat sinks with more surface area (typically larger or finer fins)
2. More mass requires more heat (energy loss) to get it up to the same temperature (especially in a short amount of time).
Looking into specific heat, the equation is:
heat added = specific heat x mass x change in temperature
In this case, the specific heat should be equal for both motors (same materials), canceling out. Same heat added and greater mass = lower temperature.

Edit: Sorry for awakening a dead thread, I just now saw the dates

Pdelcast 06.19.2013 01:00 AM

Quote:

Originally Posted by A RC Dude (Post 426938)
If you took the time to write out all the many many equations to get to the bottom of the question, i bet you'll find that the the efficiency is not dependent on the size or turn count. I bet the difference in heat comes from nothing more then the size of the motor.

The 14xl has two things keeping it cooler:
1. The more surface area allows it to cool off better, especially over time.
This is why larger, more powerful ESC's require heat sinks with more surface area (typically larger or finer fins)
2. More mass requires more heat (energy loss) to get it up to the same temperature (especially in a short amount of time).
Looking into specific heat, the equation is:
heat added = specific heat x mass x change in temperature
In this case, the specific heat should be equal for both motors (same materials), canceling out. Same heat added and greater mass = lower temperature.

Edit: Sorry for awakening a dead thread, I just now saw the dates

Good thread to awaken tho! Good info in here.

BTW -- we are planning some limited edition (very high cost) motors for sale in the near future -- watch for 'em.

A RC Dude 06.19.2013 01:31 AM

Quote:

Originally Posted by Pdelcast (Post 426941)
BTW -- we are planning some limited edition (very high cost) motors for sale in the near future -- watch for 'em.

Daja Vu huh? :lol:


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