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Wattage of Wanderer motors
Hey guys,
I couldn't locate the power rating of the various wanderer motors in the web store on this site. But ideally I'd like to be able to calculate the power levels of the various motors with varing cell counts. How would I do this? All I can find is the KV rating. -Rob |
well i've heard that the XL motors are capable of close to 1800 watts not sure about the others
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Go to http://www.bk-electronics.com/
- Enter the flag for language of choice. - Click on the left motor at the bottom center - Select Series 20 - Select Dimension All it says there is the voltage, max rpm, and current range for each size can. It's not really useful as wattage is V x A and at 40v and 120A (for the XL), that's 4,800 watts - substantially higher than I would think that small can could dissipate. Also, it would depend on the number of turns. So, in an attempt to extrapolate the wattage, I would take that 120A as the worst case amperage at the lowest turn count (6). Then, assuming that is when turning at the max rpm of 80,000. At a Kv of 2501 (which is the rated kv for the 6XL), that's about 32v. 32v x 120A is 3840W, but most people won't run these that high. Anyway, 32v/120A = .2667 ohms average. Divide that resistance by the number of turns (6) to get the "ohms per turn" (I'll call "ohms per turn" "R/T" for short), which is .0444 R/T. Now, taking the 8XL as an example, the total resistance would calculate to .0444 R/T * 8 turns = .355555 ohms total. Take whatever voltage you are running, say 18 cells (21.6v) and divide them to get current: 21.6v / .3555ohms = 60.76A. Then multiply the current and voltage to get wattage: 60.76A x 21.6v = 1312W. The total rpm would be kv x 21.5V = 40,313 rpm. 60.7A for an 8XL sounds a bit low to me, but the whole calculation is built on a lot of assumption anyway. I didn't even take the fact that these motors run 3-phase A/C voltage into consideration - that would've given me a headache. :) Yeah, I know; that was useless - but I was bored! |
The watts are limited by the cells. A good gp cell supposed to produce a 100 watts.
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A good equation for power output is Volt(amps) - resitance(amps)^2 - volts(noload current).
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Thanks guys--this helps quite a bit. I'll have to create an excel spreadsheet with graphics to comprehend it all!
For my case I'm only considering XL cans. I'd just like to see the power cross over for higher turn motors (10xl - 11xl) with lower cell counts (12) and see where they start producing some serious power. I'm thinking of perhaps an 8xl - 10xl, but starting with 12 cells, and then switching to lipos to drop some weight and add some voltage later on :) -Rob |
Brian;
You can not determine the r/t value by dividing one motor and multiply it with the turns of another. the more turns a motor has, the thinner the wires will be. with this knowledge, you'll understand why a low turn motor is able to take more A's than a high turn motor. I once saw a trustfull calculation of an 8XL, and according to that it takes 2200 watts, at a 92 percent efficiency so 176 watts is lost in the motor. |
When you lose this many watts in a motor where does it go? Is that why the motor gets hot.
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Exactly, Coolhand. The lost energy is heat.
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Bingo Leroy!
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Lol, i hear you..
They don't run AC either.. It's a PWM DC... Jokes too need some truth.. Right Daniel?? (who is dancing naked on the table when he gets a package filled with new toys from Mike) |
From what I have seen. They accually do use the same guage wire. The just wrap more of them around in the case together. But it is like running a lower guage wire in a lower turn motor.
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Now, as to Daniel's (who is that btw?) dancing habits: that's wayyy too much information! :) |
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