Quote:
Originally Posted by SpeedAssault
I think I got it, except for, if I do in series do I need a lower C than if I do in parallel to equal the same amperage ? or I guess that always stays the same ?
Are these equal ?
Two 5000 3s 30c in series = 5000 6s 30c 150amps
Two 2500 3s 30c in parallel = 5000 3s 30c 150amps
I have it all figure out except for above AND how to figure what a 2200kv motor needs in watts ?
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its equal amp wise, but obviously the 6s is double the power as voltage is 2X.
Another way to keep is straight in your head is just noting that a given battery equals a discrete amount of energy (& power.) Hooking two batts in series or par does not change the total amount of energy, ie it is two units.
EG. Energy equals power*time or (voltage*amps) * time.
A 3S 5Ah cell equals--> 3*(3.7V) *5Ah= 55.5Wh (watt hours)
So if you take two packs, the total Energy is 111Wh no matter what.
Series: ie 6S 5Ah--> 6*3.7V*5Ah=111Wh
Par: ie 3S 10Ah --->3*3.7V*10Ah=111Wh
You know the guy at the hobby store was FOS, bc according to him:
2x 3S 3Ah packs in series = 6S 6Ah... try the math
3S 3Ah= 33Wh => two packs =66Wh
LHS "magic packs": 6S 6Ah= 133 Wh... nope, fail. You didn't somehow create energy just by changing wires. If you could you'd solve the world's energy problems and win several Nobels for overturning fundamental laws of physics. lol