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MetalMan
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06.11.2009, 03:31 AM

Time for a little math...
Let's say charger/PS efficiency comes out to 70%, it should be something like that. 100watts / 0.70 = 143watts into the power supply. 143watts / 120V (into the PS, assuming you're in the US) = 1.19amps. The individual wires can't be more than probably 16ga. 3ft. of 16ga. wire has a resistance of about 0.0123ohms.

Power losses due to heat: P=I^2*R, so P=(1.19 * 1.19) * 0.0123 = 0.017watts dissipated as heat along the entire length of wire. Even if the wire were only 1in. long that shouldn't be enough to heat it up... To me it seems there's something wrong, have you inspected the exterior of the cord for the entire length?

Of course, if the wire is even 18ga. the power lost to heat would still be less than 0.03watts for 3ft. which is still nothing.


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Last edited by MetalMan; 06.11.2009 at 03:32 AM.
   
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