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11.24.2009, 01:01 PM
What is the max power rating of both channels combined? Also, what is the max voltage it will take? Some of the higher output chargers will take voltages much higher to help reduce required current.
Once you know that, simply:
power_supply_amps=charger_watts/max_input_voltage/.8
The .8 is to account for charger inefficiency.
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