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Serum
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04.07.2006, 05:31 PM

and when they turn their energy almost directly into heat, you know that the satisfaction point of the magnet is reached.


if you calculate it back, the same motors from a serie with another winding will have the same power.

Here, take a look at these measurements;

http://www.lehner-motoren.com/diagra....18v_liste.txt

http://www.lehner-motoren.com/diagra....18v_liste.txt

if you look at the poweroutput of both motors and take a look at the 800watt line, you'll see that the 1940/10 has got 28.7 N/cm of torque and the 1940/12 has got 34.05 N/cm of torque. and if you take another look at the RPM's, you'll see that the the 1940/10 delivers 28.7@26797rpm and the 1940/12 34.05@22674.

these values mean, that the motor can lift;

28.7N@101km/h
34.5N@85km/h




so the motors will deliver about the same power, but the 10L will have got more torque (untill it reaches the satisfactionpoint of the power of the magnet) then, both motors will have the same power. but with this higher torque, comes a lower RPM, and RPM X Torque = POWER and you don't run your car on torque, but on power.

Last edited by Serum; 04.08.2006 at 01:10 PM.
   
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