Capacitor For MM 4S

[BrianG]

I guess I still don't know what you are disagreeing with, but I'll assume you disagree with a previous statement I made, so I'll try to explain:

Current is going to increase when you increase the voltage, but that's because there is the same "load" on the electromagnetic nail (zero in this case).

Please correct me if I am wrong here; but in a motor, loading (among other things) plays a big role.

So, take an actual motor of whatever wind.

Apply 1v, measure current. Apply 2v, measure current. Current will increase by about a factor of 2 (probably not exactly double because rpms are higher and is inducing more opposing voltage in the adjacent coils). Is this correct?

Now, apply 1v to it and add some physical resistance to the shaft. Measure the current. Now, apply 2v, but remove the physical resistance. Measure the current. The current will not double from 1v to 2v because the load was reduced even though the voltage doubled.

So, if all other factors being equal (gearing, motor wind, etc), when going with higher voltage, current will increase. But if you gear down (on the same motor), which reduces the mechanical load, current will be less even though you increased the voltage.