Castle Holdings LLC -- our motor production facility

[brushlessboy16]

Originally Posted by Pdelcast

And it probably will perform pretty poorly. 5.0A no load, and 5.8milliohms resistance? Terrible...

Jesus! 5amp no load current on an inrunner!?

I have a big 80-100 outrunner that does 4amps with load

[nuz69]

Patrick, this isn't exactly right, there is a small amount of power which is lost in the bearings and in the air friction no ?
The motor is not really at "no load" but "air loaded".
Maybe it's only 0,5 or 1% of the no load power... What's your opinion about aerodynamics and bearings losses ?
(I doubt that a lot power is lost in the bearings anyway, other than that they would be quickly ripped apart...)

[JERRY2KONE]

No load just means that there is nothing attached to the rotor creating drag on the rotation of the shaft. The losses at no load are so miniscule that they really do not matter. The losses that really matter are shown in the comparison between the CC motor and the HK motor of the same size and spec. Those huge differences are what create the heat on a cheaper motor, where the CC motor will remain reasonable temp wise.

[sikeston34m]

Originally Posted by JERRY2KONE

No load just means that there is nothing attached to the rotor creating drag on the rotation of the shaft. The losses at no load are so miniscule that they really do not matter. The losses that really matter are shown in the comparison between the CC motor and the HK motor of the same size and spec. Those huge differences are what create the heat on a cheaper motor, where the CC motor will remain reasonable temp wise.

Yes, and we all know how Brian feels about the use of fans. LOL

All kidding aside, Castle does make a superior product.

Greatness is often imitated but never duplicated.

[Pdelcast]

Originally Posted by nuz69

Patrick, this isn't exactly right, there is a small amount of power which is lost in the bearings and in the air friction no ?
The motor is not really at "no load" but "air loaded".
Maybe it's only 0,5 or 1% of the no load power... What's your opinion about aerodynamics and bearings losses ?
(I doubt that a lot power is lost in the bearings anyway, other than that they would be quickly ripped apart...)

Yes, that's true -- bearing losses and "windage" (air drag) figure into the no-load losses. I just simplified it a bit because the majority of the losses are magnetic.

To determine what the bearing and windage losses are, you can measure no load current at, say, 6V and at 10V. The difference (usually very small) will be the contribution of bearing and windage losses.